mcoarlandh的部落格

"I was coating a winter sport and had two pieces left, one on 4, and the opposite on 2. I coiled a 6, 3, and I inspiration the activity was over, but my adversary same that I had to change place my 4 fraction to the 1 slot, afterwards embezzle the 2 off with the 6 revolution. She said I had to do this because I had the possibleness to alter my part. I've got $... awheel on this, oblige react."

We have standard more messages as the preceding one and decided to render a effectual method for beginners. The process is quite simple:

"If the number of the square block that you have involute is close or large than the figure of the row* that your checker** is situated you accept off. If the die digit is smaller than the row numeral you essential frolic that figure by wiggly your attender towards rows near minor number."

Row*: the space, the slot, the pen... that you dance or put down your board game. 24 rows be there on the backgammon floorboard.

Checker**: the stone, the chip... that you performance on the floorboard. Each participant has 15 checkers.

The way may come across tough but don't worry, it's not, let me explain! To create to take on off you should go in all your checkers into your domicile strip and in your habitation constituency you have 6 rows. Let's put a figure to respectively of these 6 rows. The firstborn one is "r1" which is as well the row that your opponent's two draughts are set on the outset of the halt.

Then you have "r2", "r3", "r4", "r5" lined squad by broadside and the later one is "r6" in which you put down 5 board game on the birth. Now you cognise that the row digit is a cipher betwixt 1 and 6. Same of the chop up number!

Now say that you have one checker in row 5 and one attendant in row 2 (better is to use your concrete backgammon flat timber and simulate those possibilities), and you have involute a "6 3", 6 is bigger than 5 and 3 is large than 2, and you carnivore off your two checkers!

Suppose you have 2 board game in "r4" and one attender in "r1", you have coiled a "4 3", you take on off one attender from "r4" next to your dice cipher 4, and for slice cipher 3 you must move one checker from "r4" to "r1".

You have 3 draughts in "r6" and 2 checkers in "r3", 4 board game in "r2" and 3 checkers in "r1". You have coiled a "5 4". Unfortunately you will transport 2 checkers from "r6" to "r2" and "r1", and you can not bear any checker off.

You have 3 draughts in "r6", 3 in "r5", 2 in "r4", 4 in "r2" and 3 in "r1", and you have rolled a "double3", because your "r3" is senseless you must reposition 2 board game from "r6" to "r3" and bear 2 board game off from "r3".

You have 3 board game in "r3", 4 board game in "r2" and 5 board game in "r1", you have involute a "5 4". You will undergo 2 board game off from "r3".

You have 2 draughts in "r6", 4 draughts in "r5", 1 attendant in "r4", 3 checkers in "r3", 3 draughts in "r2" and 2 checkers in "r1". You have involute a "double4". You will accept 1 checker off from "r4", duck 2 board game from "r6" to "r2" and 1 checker from "r5" to "r1". Only one checker has been given birth off.

Maybe the most undesirable place is when you have solitary two checkers outstanding in "r2" and you gyration one "1", for occasion a "3 1". While 3 is larger than "r2", 1 is smaller, and you will carry one attender off but transport the final one to "r1" and suspension for the adjacent mitt. Same for "2 1" or "4 1"